Hi. Need help with creating the ‘for’ macro. It must take a parameter, an initial value, an end value, and a loop step. Macro must return amount of iteration. Various operations should take place inside it. It should be designed without leaks.The preliminary version looks like this:

(defmacro for ((param-name start-value end-value &optional (step1 1)) &body body)
  (let* ((func-name (gensym))
(start (gensym))
(param-name (gensym))
(comparison (if (< step1 0) '< '>))
(end (gensym))
(step (gensym))
(k (gensym)))
'(labels ((,func-name (,param-name ,start ,end ,step ,k)
(let ((new-exprs (progn ,@body))
(newK (+ 1 ,k)))
(if (,comparison ,end ,param-name)
(,func-name (+ ,param-name ,step) ,start ,end ,step newK)
newK))))
(,func-name ,param-name ,start-value ,end-value ,step1 0))))

I understand that it looks terrible. I don’t understand how you can access the parameter without violating the rule about leaks.

  • Revolutionary_UtenaOPB
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    1 year ago

    The teacher said to do it this way. As I understand it, when using a macro, you need to refer to a parameter, for example (let ((s 0))

    (for (i 2 N)

    ((inch s (sin i)))

    s) Here it is necessary to refer to the modified sh. Therefore, it is passed to the recursive param-name call.