0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 18 hours agoNot my problem sortinfosec.pubimagemessage-square50fedilinkarrow-up1588arrow-down110
arrow-up1578arrow-down1imageNot my problem sortinfosec.pub0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 18 hours agomessage-square50fedilink
minus-squarefrezik@midwest.sociallinkfedilinkarrow-up43·17 hours agoYou still have to check that it’s sorted, which is O(n). We’ll also assume that destroying the universe takes constant time.
minus-squareBatmanAoD@programming.devlinkfedilinkarrow-up37·16 hours agoIn the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
minus-squaregroet@feddit.orglinkfedilinkEnglisharrow-up9·12 hours agoIt actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
minus-squareBenjaben@lemmy.worldlinkfedilinkarrow-up8·12 hours ago We’ll also assume that destroying the universe takes constant time. Well yeah just delete the pointer to it!
You still have to check that it’s sorted, which is O(n).
We’ll also assume that destroying the universe takes constant time.
In the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
It actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
Eh, trillion is a constant
amortized O(0)
Well yeah just delete the pointer to it!
universe.take()